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Question Number 183330 by Matica last updated on 25/Dec/22

S = sinhx+sinh^2 x + sinh^3 x+...+sinh^n x=?

$$\:\:{S}\:=\:{sinhx}+{sinh}^{\mathrm{2}} {x}\:+\:{sinh}^{\mathrm{3}} {x}+...+{sinh}^{{n}} {x}=? \\ $$

Commented by mokys last updated on 25/Dec/22

S = ((sinhx)/(1−sinhx))

$${S}\:=\:\frac{{sinhx}}{\mathrm{1}−{sinhx}} \\ $$

Commented by Ar Brandon last updated on 25/Dec/22

Isn't this rather the sum to infinity?

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