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Question Number 9382 by sandipkd@ last updated on 03/Dec/16

Commented by sandipkd@ last updated on 03/Dec/16

question no. 9?

$${question}\:{no}.\:\mathrm{9}? \\ $$

Answered by mrW last updated on 03/Dec/16

question 9: a=(dv/dt)=(dv/ds)×(ds/dt)=(dv/ds)×v=4×tan 60°=4(√3) m/s^2 ⇒ (a) is correct question 10: x_1 =(1/2)gt^2 ⇒ 2x_1 =gt^2 ...(i) x_1 +x_2 =(1/2)g(2t)^2 =2gt^2 ...(ii) (ii)−(i) ⇒ x_2 −x_1 =gt^2 t=(√((x_2 −x_1 )/g)) ⇒ (a) is correct

$$\mathrm{question}\:\mathrm{9}: \\ $$$$\mathrm{a}=\frac{\mathrm{dv}}{\mathrm{dt}}=\frac{\mathrm{dv}}{\mathrm{ds}}×\frac{\mathrm{ds}}{\mathrm{dt}}=\frac{\mathrm{dv}}{\mathrm{ds}}×\mathrm{v}=\mathrm{4}×\mathrm{tan}\:\mathrm{60}°=\mathrm{4}\sqrt{\mathrm{3}}\:\mathrm{m}/\mathrm{s}^{\mathrm{2}} \\ $$$$\Rightarrow\:\left(\mathrm{a}\right)\:\mathrm{is}\:\mathrm{correct} \\ $$$$ \\ $$$$\mathrm{question}\:\mathrm{10}: \\ $$$$\mathrm{x}_{\mathrm{1}} =\frac{\mathrm{1}}{\mathrm{2}}\mathrm{gt}^{\mathrm{2}} \\ $$$$\Rightarrow\:\mathrm{2x}_{\mathrm{1}} =\mathrm{gt}^{\mathrm{2}} \:\:\:\:\:...\left(\mathrm{i}\right) \\ $$$$\mathrm{x}_{\mathrm{1}} +\mathrm{x}_{\mathrm{2}} =\frac{\mathrm{1}}{\mathrm{2}}\mathrm{g}\left(\mathrm{2t}\right)^{\mathrm{2}} =\mathrm{2gt}^{\mathrm{2}} \:\:\:\:\:\:\:...\left(\mathrm{ii}\right) \\ $$$$\left(\mathrm{ii}\right)−\left(\mathrm{i}\right) \\ $$$$\Rightarrow\:\mathrm{x}_{\mathrm{2}} −\mathrm{x}_{\mathrm{1}} =\mathrm{gt}^{\mathrm{2}} \\ $$$$\mathrm{t}=\sqrt{\frac{\mathrm{x}_{\mathrm{2}} −\mathrm{x}_{\mathrm{1}} }{\mathrm{g}}} \\ $$$$\Rightarrow\:\left(\mathrm{a}\right)\:\mathrm{is}\:\mathrm{correct} \\ $$

Commented by sandipkd@ last updated on 03/Dec/16

thanks bro

$${thanks}\:{bro} \\ $$

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