Question Number 90706 by I want to learn more last updated on 25/Apr/20 | ||
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Commented by jagoll last updated on 25/Apr/20 | ||
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$${t}\:=\:\sqrt{\mathrm{4}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} }\:=\:\mathrm{5} \\ $$$${x}\:=\:\sqrt{\mathrm{5}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} }=\:\mathrm{4} \\ $$$$ \\ $$ | ||
Answered by mr W last updated on 25/Apr/20 | ||
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Commented by jagoll last updated on 25/Apr/20 | ||
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$${AC}\:=\:\mathrm{4}.\:{AB}\:=\:\mathrm{5} \\ $$$${then}\:{x}\:=\:\mathrm{4} \\ $$ | ||
Commented by jagoll last updated on 25/Apr/20 | ||
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$${yeah}...{my}\:{answer}\:{is}\:{correct} \\ $$ | ||
Commented by I want to learn more last updated on 25/Apr/20 | ||
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$$\mathrm{Thanks}\:\mathrm{sir} \\ $$ | ||
Answered by I want to learn more last updated on 25/Apr/20 | ||
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$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$ | ||