Question Number 90360 by TawaTawa1 last updated on 23/Apr/20 | ||
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Commented by TawaTawa1 last updated on 23/Apr/20 | ||
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$$\mathrm{Please}\:\mathrm{help} \\ $$$$ \\ $$ | ||
Answered by frc2crc last updated on 23/Apr/20 | ||
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$${if}\:{z}={x}+{iy}\:{and}\:\zeta\left({z}\right)=\mathrm{0}\:{then}\:{x}=\frac{\mathrm{1}}{\mathrm{2}} \\ $$ | ||