Question Number 89755 by naka3546 last updated on 19/Apr/20 | ||
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Commented by john santu last updated on 19/Apr/20 | ||
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$$\mathrm{576}\:{cm}^{\mathrm{2}} \\ $$ | ||
Answered by $@ty@m123 last updated on 19/Apr/20 | ||
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$${A}=\mathrm{24}^{\mathrm{2}} −\pi×\mathrm{12}^{\mathrm{2}} \\ $$$$=\mathrm{576}−\mathrm{144}\pi \\ $$$$=\mathrm{123}\frac{\mathrm{3}}{\mathrm{7}}\:{cm}^{\mathrm{2}} \\ $$ | ||
Commented by $@ty@m123 last updated on 19/Apr/20 | ||
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Commented by john santu last updated on 19/Apr/20 | ||
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Commented by john santu last updated on 19/Apr/20 | ||
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$${I}\:=\:\mathrm{24}^{\mathrm{2}} −\mathrm{144}\pi \\ $$$${II}\:=\:\mathrm{144}\pi \\ $$$${shaded}\:{area}\:=\:{I}+{II}\:=\:\mathrm{576} \\ $$ | ||
Commented by $@ty@m123 last updated on 19/Apr/20 | ||
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$${Oh}...{Yes}. \\ $$$${Thanks}\:{for}\:{correction}. \\ $$ | ||