Question Number 86379 by jagoll last updated on 28/Mar/20
Commented by jagoll last updated on 28/Mar/20
$$\mathrm{to}\:\mathrm{miss}\:\mathrm{tawa} \\ $$
Commented by TawaTawa1 last updated on 28/Mar/20
$$\mathrm{Sir},\:\mathrm{am}\:\mathrm{here} \\ $$
Answered by jagoll last updated on 28/Mar/20
$$\mathrm{tan}\:\mathrm{30}^{\mathrm{o}} \:=\:\frac{\mathrm{9}}{\mathrm{AS}}\:\Rightarrow\:\mathrm{AS}\:=\:\mathrm{9}\sqrt{\mathrm{3}} \\ $$$$\mathrm{tan}\:\mathrm{60}^{\mathrm{o}} \:=\:\frac{\mathrm{9}}{\mathrm{DP}}\:\Rightarrow\:\mathrm{DP}\:=\:\mathrm{3}\sqrt{\mathrm{3}} \\ $$$$\mathrm{perimeter}\:\mathrm{PQRS}\:=\:\mathrm{2}×\left(\mathrm{18}\sqrt{\mathrm{3}}\:+\:\mathrm{6}\sqrt{\mathrm{3}}\right) \\ $$$$=\:\mathrm{48}\sqrt{\mathrm{3}}\:\mathrm{cm} \\ $$
Commented by TawaTawa1 last updated on 28/Mar/20
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{I}\:\mathrm{appreciate}. \\ $$
Commented by Prithwish Sen 1 last updated on 28/Mar/20
$$\mathrm{is}'\mathrm{nt}\:\mathrm{it}\:\mathrm{48}\sqrt{\mathrm{3}}\:\mathrm{cm}. \\ $$
Commented by jagoll last updated on 28/Mar/20
$$\mathrm{oo}\:\mathrm{yes}.\:\mathrm{i}'\mathrm{m}\:\mathrm{forgot}\:\mathrm{multiply}\:\mathrm{by}\:\mathrm{2} \\ $$