Question Number 77848 by jagoll last updated on 11/Jan/20 | ||
![]() | ||
Commented by jagoll last updated on 11/Jan/20 | ||
![]() | ||
$${dear}\:{sir}\:{W} \\ $$$${look}\:{picture}\: \\ $$$${correct}\:{a}\:=\:\sqrt{{b}×{c}}? \\ $$ | ||
Commented by mr W last updated on 11/Jan/20 | ||
![]() | ||
$$\frac{{b}−{a}}{{b}+{a}}=\frac{{a}−{c}}{{a}+{c}} \\ $$$${ab}−{a}^{\mathrm{2}} +{bc}−{ac}={ab}+{a}^{\mathrm{2}} −{bc}−{ac} \\ $$$${a}^{\mathrm{2}} ={bc} \\ $$$$\Rightarrow{a}=\sqrt{{bc}} \\ $$ | ||
Commented by jagoll last updated on 11/Jan/20 | ||
![]() | ||
$${waw}...\:{thanks}\:{you}\:{sir} \\ $$ | ||