Question Number 76220 by Master last updated on 25/Dec/19
Commented by benjo last updated on 25/Dec/19
$$\mathrm{waw}..\mathrm{this}\:\mathrm{problem}\:\mathrm{very}\:\mathrm{nice} \\ $$
Answered by MJS last updated on 25/Dec/19
$$\int{x}!{dx}=\int\Gamma\left({x}+\mathrm{1}\right){dx}=\int\underset{\mathrm{0}} {\overset{\infty} {\int}}\mathrm{e}^{−{t}} {t}^{{x}−\mathrm{1}} {dtdx} \\ $$$$\mathrm{and}\:\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{think}\:\mathrm{this}\:\mathrm{can}\:\mathrm{be}\:\mathrm{solved}... \\ $$