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Question Number 71972 by device4438043516@gmail.com last updated on 23/May/20 | ||
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Commented by MJS last updated on 23/Oct/19 | ||
$$\mathrm{syntax}\:\mathrm{unknown} \\ $$$${u}={u}\left({x}\right) \\ $$$${v}={v}\left({x}\right) \\ $$$$\frac{{d}}{{dx}}\left[{u}×{v}\right]={u}'×{v}+{u}×{v}' \\ $$$$\mathrm{or}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{keep}\:\mathrm{in}\:\mathrm{mind}: \\ $$$$\left({uv}\right)'={u}'{v}+{uv}' \\ $$ | ||
Commented by benjo last updated on 25/Dec/19 | ||
$$\mathrm{what}\:\mathrm{is}\:\mathrm{this}\:\mathrm{sir}? \\ $$ | ||