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Question Number 70746 by Rio Michael last updated on 07/Oct/19 | ||
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Commented by Rio Michael last updated on 07/Oct/19 | ||
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$${from}\:{the}\:{above}\:{circuit} \\ $$$$\left.{a}\right){calculate}\:{the}\:{current}\:{flowing}\:{through}\:{the}\:{resistor}\:{R} \\ $$$$\left.{b}\right)\:{find}\:{the}\:{value}\:{of}\:{R} \\ $$$$\left.{c}\right)\:{find}\:{the}\:{emf}\:{E}\: \\ $$ | ||
Commented by prakash jain last updated on 08/Oct/19 | ||
out of 3A current 1A is going in left branch so 2A will go in right brnach and equal to current thru R. 2R+3×3=15 R=3 | ||
Commented by prakash jain last updated on 08/Oct/19 | ||
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$$\mathrm{E}=\mathrm{3}×\mathrm{3}+\mathrm{6}×\mathrm{1} \\ $$ | ||
Commented by Rio Michael last updated on 12/Oct/19 | ||
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$${thanks}\: \\ $$ | ||