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Question Number 69866 by Askash last updated on 28/Sep/19
Answered by mr W last updated on 28/Sep/19
Commented by mr W last updated on 28/Sep/19
$$\frac{\mathrm{1}}{\frac{\mathrm{1}}{\mathrm{4}}+\frac{\mathrm{1}}{\mathrm{4}}}=\mathrm{2}\:\Omega \\ $$$$\mathrm{2}+\mathrm{2}=\mathrm{4}\:\Omega \\ $$$${I}=\frac{{E}}{{R}}=\frac{\mathrm{2}{V}}{\mathrm{4}\Omega}=\mathrm{0}.\mathrm{5}\:{A}\:\:\Rightarrow\:{answer} \\ $$