Question Number 69645 by ahmadshahhimat775@gmail.com last updated on 26/Sep/19 | ||
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Answered by Rasheed.Sindhi last updated on 26/Sep/19 | ||
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$$\sqrt{{x}+\sqrt{{x}+\sqrt{{x}....}}}=\mathrm{2} \\ $$$$\left(\sqrt{{x}+\sqrt{{x}+\sqrt{{x}....}}}\right)=\left(\mathrm{2}\right)^{\mathrm{2}} \\ $$$${x}+\sqrt{{x}+\sqrt{{x}+\sqrt{{x}...}}}=\mathrm{4} \\ $$$${x}+\mathrm{2}=\mathrm{4} \\ $$$${x}=\mathrm{2} \\ $$ | ||