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Question Number 63430 by rajesh4661kumar@gamil.com last updated on 04/Jul/19

Answered by MJS last updated on 04/Jul/19

y=sin^(−1) (√(x−1)) 1≤x≤2 ⇒ 0≤(√(x−1))≤1 ⇒ ⇒ 0≤y≤(π/2)

y=sin−1x−11⩽x⩽2⇒0⩽x−1⩽1⇒⇒0⩽y⩽π2

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