Question Number 63103 by aseer imad last updated on 29/Jun/19 | ||
Commented by aseer imad last updated on 29/Jun/19 | ||
how to do this...Tia. | ||
Commented by Hope last updated on 29/Jun/19 | ||
Answered by Hope last updated on 29/Jun/19 | ||
$${F}×\mathrm{50}×\mathrm{10}^{−\mathrm{2}} =\mathrm{90}×\mathrm{9}.\mathrm{8}×\mathrm{40}×\mathrm{10}^{−\mathrm{2}} \\ $$$${F}=\frac{\mathrm{90}×\mathrm{9}.\mathrm{8}×\mathrm{40}×\mathrm{10}^{−\mathrm{2}} }{\mathrm{50}×\mathrm{10}^{−\mathrm{2}} }=\mathrm{705}.\mathrm{6} \\ $$$$ \\ $$ | ||