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Question Number 59323 by Tawa1 last updated on 08/May/19

Answered by tanmay last updated on 08/May/19

when cab catch bus that both cover same distance  d_(cab) =(1/2)×2×t^2   d_(bus) =30(t+5)  t^2 =30t+150  t^2 −30t−150=0  t^2 −2×t×15+225=150+225  (t−15)^2 =375  t=15+5(√(15))   t≈34.36sec  d_(cab) =t^2   d_(cab) ≈1180.61 meter

$${when}\:{cab}\:{catch}\:{bus}\:{that}\:{both}\:{cover}\:{same}\:{distance} \\ $$$${d}_{{cab}} =\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{2}×{t}^{\mathrm{2}} \\ $$$${d}_{{bus}} =\mathrm{30}\left({t}+\mathrm{5}\right) \\ $$$${t}^{\mathrm{2}} =\mathrm{30}{t}+\mathrm{150} \\ $$$${t}^{\mathrm{2}} −\mathrm{30}{t}−\mathrm{150}=\mathrm{0} \\ $$$${t}^{\mathrm{2}} −\mathrm{2}×{t}×\mathrm{15}+\mathrm{225}=\mathrm{150}+\mathrm{225} \\ $$$$\left({t}−\mathrm{15}\right)^{\mathrm{2}} =\mathrm{375} \\ $$$${t}=\mathrm{15}+\mathrm{5}\sqrt{\mathrm{15}}\: \\ $$$${t}\approx\mathrm{34}.\mathrm{36}{sec} \\ $$$${d}_{{cab}} ={t}^{\mathrm{2}} \\ $$$${d}_{{cab}} \approx\mathrm{1180}.\mathrm{61}\:{meter} \\ $$

Commented by Tawa1 last updated on 08/May/19

God bless you sir

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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