Question Number 5632 by sanusihammed last updated on 23/May/16 | ||
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Answered by FilupSmith last updated on 23/May/16 | ||
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$$\mathrm{Exterior}\:\mathrm{angles}\:=\:\mathrm{360}^{\mathrm{o}} \\ $$$$\mathrm{2}{x}+\mathrm{3}{x}+{x}−\mathrm{40}+{x}+\mathrm{10}+{x}−\mathrm{60}=\mathrm{360} \\ $$$$\mathrm{8}{x}−\mathrm{90}=\mathrm{360} \\ $$$$\mathrm{8}{x}=\mathrm{450} \\ $$$${x}=\frac{\mathrm{450}}{\mathrm{8}} \\ $$ | ||
Commented by sanusihammed last updated on 23/May/16 | ||
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$${Thanks}\:{so}\:{much} \\ $$ | ||