Question Number 55104 by Gulay last updated on 17/Feb/19 | ||
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Commented by Gulay last updated on 17/Feb/19 | ||
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$$\mathrm{sir}\:\mathrm{could}\:\mathrm{you}\:\mathrm{help}\:\mathrm{me}??? \\ $$$$\mathrm{plz}\:\mathrm{help}\:\mathrm{me}\:\mathrm{sir} \\ $$ | ||
Commented by math1967 last updated on 17/Feb/19 | ||
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$$\:{a}^{{log}_{{a}} {x}} ={x}\:\:\:\therefore\:\mathrm{2}^{{log}_{\mathrm{2}} \mathrm{8}} =\mathrm{8} \\ $$$$\:\mathrm{3}^{{log}_{\mathrm{3}} \mathrm{9}} =\mathrm{9} \\ $$$$ \\ $$ | ||
Commented by Gulay last updated on 18/Feb/19 | ||
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$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$ | ||