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Question Number 53328 by Tawa1 last updated on 20/Jan/19

Commented by maxmathsup by imad last updated on 20/Jan/19

f(x)=tanxsinx =((sin^2 x)/(cosx)) .

$${f}\left({x}\right)={tanxsinx}\:=\frac{{sin}^{\mathrm{2}} {x}}{{cosx}}\:. \\ $$

Commented by Tawa1 last updated on 20/Jan/19

God bless you sir

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

Answered by tanmay.chaudhury50@gmail.com last updated on 20/Jan/19

f(x)=tan(π+x)cos(x−(π/2))  =(tanx)×sinx       =((sin^2 x)/(cosx))

$${f}\left({x}\right)={tan}\left(\pi+{x}\right){cos}\left({x}−\frac{\pi}{\mathrm{2}}\right) \\ $$$$=\left({tanx}\right)×{sinx}\: \\ $$$$\:\: \\ $$$$=\frac{{sin}^{\mathrm{2}} {x}}{{cosx}} \\ $$

Commented by Tawa1 last updated on 20/Jan/19

God bless you sir

$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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