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Question Number 52031 by Necxx last updated on 02/Jan/19 | ||
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Commented by Necxx last updated on 02/Jan/19 | ||
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$$\mathrm{3}\:{and}\:\mathrm{4}\:{please}.\:{Thanks}\:{in}\:{advance} \\ $$ | ||
Answered by afachri last updated on 02/Jan/19 | ||
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Answered by afachri last updated on 02/Jan/19 | ||
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$$\left(\mathrm{4}\right) \\ $$$${n}\left(\mathrm{A}\right)\:\:=\:\:\:{n}\left(\mathrm{B}\right)\:\:\:=\:\:\:\mathrm{3}\:\mathrm{ways}\:\:\:\:\left\{\left(\mathrm{4};\mathrm{6}\right)\:,\:\left(\mathrm{5};\mathrm{5}\right)\:,\:\left(\mathrm{6};\mathrm{4}\right)\right\} \\ $$$${n}\left(\mathrm{S}\right)\:\:\:=\:\mathrm{36}\:\mathrm{ways} \\ $$$$ \\ $$$$\mathrm{if}\:\mathrm{A}\:\mathrm{starts}\:\mathrm{first},\:\mathrm{then}\:\:: \\ $$$$\mathrm{1}.\:\:\:{P}\left(\mathrm{A}\right)\:=\:\frac{\mathrm{3}}{\mathrm{36}}\:=\:\mathrm{0}.\mathrm{0833} \\ $$$$\mathrm{2}.\:\:\:{P}\left(\mathrm{B}\right)\:\:\Rightarrow\:\:\left(\frac{\mathrm{3}\:+\:\mathrm{30}}{\mathrm{36}}\right)×\frac{\mathrm{3}}{\mathrm{36}}\:=\:\mathrm{0}.\mathrm{0764} \\ $$$$ \\ $$ | ||
Commented by Necxx last updated on 03/Jan/19 | ||
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$${Thank}\:{you}\:{sir}.\:{Its}\:{clear}\:{even}\:{though} \\ $$$${I}\:{dont}\:{know}\:{the}\:{answer}. \\ $$ | ||