Question Number 51636 by mr W last updated on 29/Dec/18
Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18
Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18
$${radius}\:{quadrant}={R}\:\:\:{radius}\:{semicircle}={r} \\ $$$${r}^{\mathrm{2}} +\left({r}\sqrt{\mathrm{2}}\:\right)^{\mathrm{2}} ={R}^{\mathrm{2}} \\ $$$$\mathrm{3}{r}^{\mathrm{2}} ={R}^{\mathrm{2}} \\ $$$$\frac{{area}\:{semicircle}}{{area}\:{quadrant}}=\frac{\frac{\pi{r}^{\mathrm{2}} }{\mathrm{2}}}{\frac{\pi{R}^{\mathrm{2}} }{\mathrm{4}}}=\frac{\mathrm{2}{r}^{\mathrm{2}} }{{R}^{\mathrm{2}} }=\frac{\mathrm{2}{r}^{\mathrm{2}} }{\mathrm{3}{r}^{\mathrm{2}} }=\frac{\mathrm{2}}{\mathrm{3}} \\ $$
Commented by mr W last updated on 29/Dec/18
$${perfect}\:{sir}! \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 29/Dec/18
$${thank}\:{you}\:{sir}... \\ $$
Answered by afachri last updated on 29/Dec/18
$$\frac{\mathrm{2}}{\mathrm{3}}\: \\ $$
Commented by afachri last updated on 29/Dec/18
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{Sir}. \\ $$
Commented by mr W last updated on 29/Dec/18
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Commented by Tawa1 last updated on 29/Dec/18
$$\mathrm{Sir},\:\:\mathrm{please}\:\mathrm{help}\:\mathrm{me}\:\mathrm{look}\:\mathrm{at}\:\mathrm{question}\:\:\mathrm{51644} \\ $$