Question Number 51289 by rahul 19 last updated on 25/Dec/18 | ||
Commented by Tinkutara last updated on 26/Dec/18 | ||
Ohh sorry! Thanks! | ||
Commented by rahul 19 last updated on 26/Dec/18 | ||
when negative charge is formed in option 3 , it will become AROMATIC. (this is Exact reason). | ||
Commented by Tinkutara last updated on 26/Dec/18 | ||
Na2CO3 extracts acidic hydrogen so when negative charge is formed in option 3, it has maximum number of resonating structures. (I am not sure though) | ||
Commented by Tinkutara last updated on 26/Dec/18 | ||
But 1st also becomes aromatic with negative charge on the top vertex. | ||
Commented by rahul 19 last updated on 26/Dec/18 | ||
Nahh, it will become Anti-Aromatic. It would have become aromatic if it were to have +ve charge at top vertex! | ||
Answered by afachri last updated on 25/Dec/18 | ||
$$\left(\mathrm{1}\right)\:\mathrm{siklopropena} \\ $$ | ||
Commented by rahul 19 last updated on 25/Dec/18 | ||
$${Ans}\:{is}\:\left(\mathrm{3}\right)\:. \\ $$ | ||
Commented by afachri last updated on 25/Dec/18 | ||
$$\mathrm{uhm}\:\mathrm{i}\:\mathrm{was}\:\mathrm{wrong}\:\mathrm{Sir}.\:\mathrm{so}\:\mathrm{that}\:\mathrm{the}\:\mathrm{point}\:\mathrm{is},\: \\ $$$$\mathrm{cause}\:\mathrm{the}\:\left(\mathrm{3}\right)\:\mathrm{compunds}\:\mathrm{has}\:\mathrm{more}\:\mathrm{double} \\ $$$$\mathrm{bonds}\:\mathrm{than}\:\mathrm{the}\:\mathrm{others}\:\left(\mathrm{cyclohexena}\:\mathrm{excluded}\right. \\ $$$$\left.\mathrm{cause}\:\mathrm{it}'\mathrm{s}\:\mathrm{stable}\right).\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{double} \\ $$$$\mathrm{bonds}\:\mathrm{affects}\:\mathrm{reactivity}\:\mathrm{compounds}. \\ $$$$\mathrm{thanks}\:\mathrm{Sir}\:\mathrm{for}\:\mathrm{sharing}\:\mathrm{this}\:\mathrm{question}. \\ $$ | ||