Question Number 48310 by rahul 19 last updated on 22/Nov/18 | ||
Answered by tanmay.chaudhury50@gmail.com last updated on 22/Nov/18 | ||
$${current}\:{I}=\frac{{dq}}{{dt}} \\ $$$${E}=\frac{{q}}{{c}}\:\:{so}\:\frac{{dE}}{{dt}}=\frac{{I}}{{c}}\:\:\:{I}={c}\frac{{dE}}{{dt}} \\ $$$${force}\:{on}\:{coducting}\:{slider}\:{F}={IBl} \\ $$$${F}={m}\frac{{dV}}{{dt}}={IBl} \\ $$$${m}\frac{{dV}}{{dt}}={c}\frac{{dE}}{{dt}}{Bl} \\ $$$${dV}=\frac{{cBl}}{{m}}{dE} \\ $$$$\int_{\mathrm{0}} ^{{V}} {dV}=\frac{{cBl}}{{m}}\int_{\mathrm{0}} ^{{E}} {dE} \\ $$$${V}=\frac{{BclE}}{{m}}\:\:\:{pls}\:{check}\:{is}\:{the}\:{answer}\:{correct}... \\ $$ | ||
Commented by rahul 19 last updated on 22/Nov/18 | ||
$${Sir},\:{ans}.\:{is}\:{D}... \\ $$$${but}\:{your}\:{method}\:{seems}\:{correct}! \\ $$ | ||