Question Number 46088 by Cheyboy last updated on 21/Oct/18
Answered by $@ty@m last updated on 21/Oct/18
![Let Solution set = [(a,b),(c,d) ] a+b=8 ...(1) b+d=8 ...(2) ⇒a=d ...(3) c−d=6 ...(4) a+c=13 ...(5) (3)&(5)⇒c+d=13 ...(6) (4) & (6)⇒c=9.5 ⇒d=3.5 ⇒a=3.5 ⇒b=4.5 ∴ Solution set [(a,b),(c,d) ]= [((3.5),(4.5)),((9.5),(3.5)) ]](Q46089.png)
$${Let}\:{Solution}\:{set}\:=\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix} \\ $$$${a}+{b}=\mathrm{8}\:...\left(\mathrm{1}\right) \\ $$$${b}+{d}=\mathrm{8}\:...\left(\mathrm{2}\right) \\ $$$$\Rightarrow{a}={d}\:...\left(\mathrm{3}\right) \\ $$$${c}−{d}=\mathrm{6}\:...\left(\mathrm{4}\right) \\ $$$${a}+{c}=\mathrm{13}\:...\left(\mathrm{5}\right) \\ $$$$\left(\mathrm{3}\right)\&\left(\mathrm{5}\right)\Rightarrow{c}+{d}=\mathrm{13}\:...\left(\mathrm{6}\right) \\ $$$$\left(\mathrm{4}\right)\:\&\:\left(\mathrm{6}\right)\Rightarrow{c}=\mathrm{9}.\mathrm{5} \\ $$$$\Rightarrow{d}=\mathrm{3}.\mathrm{5} \\ $$$$\Rightarrow{a}=\mathrm{3}.\mathrm{5} \\ $$$$\Rightarrow{b}=\mathrm{4}.\mathrm{5} \\ $$$$\therefore\:{Solution}\:{set}\:\begin{bmatrix}{{a}}&{{b}}\\{{c}}&{{d}}\end{bmatrix}=\begin{bmatrix}{\mathrm{3}.\mathrm{5}}&{\mathrm{4}.\mathrm{5}}\\{\mathrm{9}.\mathrm{5}}&{\mathrm{3}.\mathrm{5}}\end{bmatrix} \\ $$
Commented by Cheyboy last updated on 21/Oct/18
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{sir} \\ $$$$ \\ $$$$ \\ $$