Question Number 45609 by peter frank last updated on 14/Oct/18 | ||
![]() | ||
Commented by MrW3 last updated on 14/Oct/18 | ||
![]() | ||
$$\frac{{b}}{\mathrm{sin}\:{B}}=\frac{{a}}{\mathrm{sin}\:{A}}=\frac{{a}}{\mathrm{sin}\:\left({B}+{C}\right)} \\ $$$$\Rightarrow{b}={a}\frac{\mathrm{sin}\:{B}}{\mathrm{sin}\:\left({B}+{C}\right)} \\ $$$${Area}=\frac{\mathrm{1}}{\mathrm{2}}{ab}\:\mathrm{sin}\:{C}=\frac{{a}^{\mathrm{2}} \mathrm{sin}\:{B}\:\mathrm{sin}\:{C}}{\mathrm{2}\:\mathrm{sin}\:\left({B}+{C}\right)} \\ $$$$ \\ $$$${but}\:{this}\:{has}\:{nothing}\:{to}\:{do}\:{with}\:{s}. \\ $$ | ||
Commented by peter frank last updated on 14/Oct/18 | ||
![]() | ||
$$\mathrm{thanks} \\ $$ | ||
Commented by peter frank last updated on 14/Oct/18 | ||
![]() | ||
$$\mathrm{help}\:\mathrm{sir}\:\:\mathrm{Qn}\:\mathrm{45514} \\ $$ | ||