Question Number 44373 by jasno91 last updated on 28/Sep/18 | ||
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Answered by tanmay.chaudhury50@gmail.com last updated on 28/Sep/18 | ||
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$${a}^{\mathrm{2}} =\mathrm{484} \\ $$$${a}=\sqrt{\mathrm{484}} \\ $$$$\:\:\:\:=\sqrt{\mathrm{4}×\mathrm{121}}\: \\ $$$$\:\:\:\:\:=\mathrm{2}×\mathrm{11} \\ $$$${perimeter}\:\mathrm{4}{a} \\ $$$$=\mathrm{4}×\mathrm{22}=\mathrm{88}\:{m} \\ $$ | ||