Question Number 43713 by Junaid555 last updated on 14/Sep/18 | ||
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Commented by Cheyboy last updated on 14/Sep/18 | ||
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$$\sqrt{\frac{\left(\mathrm{6}^{\mathrm{3}} \right)^{\mathrm{2}/\mathrm{3}} \left(\mathrm{5}^{\mathrm{2}} \right)^{\mathrm{1}/\mathrm{2}} }{\left(\mathrm{5}^{−\mathrm{2}} \right)^{−\mathrm{3}/\mathrm{2}} }\:}=\sqrt{\frac{\left(\mathrm{6}^{\mathrm{2}} \right)\left(\mathrm{5}\right)}{\left(\mathrm{5}^{\mathrm{3}} \right)}} \\ $$$$=\sqrt{\frac{\mathrm{36}}{\mathrm{25}}}=\frac{\mathrm{4}}{\mathrm{5}} \\ $$ | ||
Commented by Junaid555 last updated on 14/Sep/18 | ||
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$${Thanks}\:{dear} \\ $$ | ||