Question Number 4329 by Rasheed Soomro last updated on 10/Jan/16 | ||
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Commented by prakash jain last updated on 10/Jan/16 | ||
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$$\mathrm{square}/\mathrm{8}+\mathrm{traingle}/\mathrm{4}=\mathrm{12}\:\mathrm{parts} \\ $$$$\mathrm{each}\:\mathrm{part}\:\mathrm{gets}\:\mathrm{3}. \\ $$ | ||
Answered by Rasheed Soomro last updated on 11/Jan/16 | ||
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