Question Number 41009 by Raj Singh last updated on 31/Jul/18 | ||
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Commented by $@ty@m last updated on 31/Jul/18 | ||
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Answered by $@ty@m last updated on 31/Jul/18 | ||
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$$\angle{C}=\angle{A}\:\:\:\left({corresponding}\:{angles}\right)....\left(\mathrm{1}\right) \\ $$$$\angle{A}=\angle{F}\:\:\left({opposite}\:{angles}\right)\:....\left(\mathrm{2}\right) \\ $$$${from}\:\left(\mathrm{1}\right)\:{and}\:\left(\mathrm{2}\right) \\ $$$$\angle{C}=\angle{F} \\ $$$${Q}.{E}.{D}. \\ $$ | ||