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Question Number 35197 by Tinkutara last updated on 16/May/18

Answered by ajfour last updated on 17/May/18

  ⇒ P = ((3×320)/(290)) atm =((96)/(29))atm            =((96)/(30−1))=((96)/(30))(1+(1/(30)))             =3.2+((3.2)/(30)) = 3.31atm  ((n−△n)/3)=(n/(3.31))  ⇒  1−((△n)/n)=(3/(3.31))  or   ((△n)/n)=((0.31)/(3.31)) =((△V∣_(3.31atm) )/(V∣_(3.31atm) =10 l))  ⇒ (△V)_(1atm) =(△V)_(3.31atm) ×3.31                 =10×((0.31)/(3.31))×3.31                 =3.1 litres.

$$ \\ $$$$\Rightarrow\:{P}\:=\:\frac{\mathrm{3}×\mathrm{320}}{\mathrm{290}}\:{atm}\:=\frac{\mathrm{96}}{\mathrm{29}}{atm} \\ $$$$\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{96}}{\mathrm{30}−\mathrm{1}}=\frac{\mathrm{96}}{\mathrm{30}}\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{30}}\right)\: \\ $$$$\:\:\:\:\:\:\:\:\:\:=\mathrm{3}.\mathrm{2}+\frac{\mathrm{3}.\mathrm{2}}{\mathrm{30}}\:=\:\mathrm{3}.\mathrm{31}{atm} \\ $$$$\frac{{n}−\bigtriangleup{n}}{\mathrm{3}}=\frac{{n}}{\mathrm{3}.\mathrm{31}} \\ $$$$\Rightarrow\:\:\mathrm{1}−\frac{\bigtriangleup{n}}{{n}}=\frac{\mathrm{3}}{\mathrm{3}.\mathrm{31}} \\ $$$${or}\:\:\:\frac{\bigtriangleup{n}}{{n}}=\frac{\mathrm{0}.\mathrm{31}}{\mathrm{3}.\mathrm{31}}\:=\frac{\bigtriangleup{V}\mid_{\mathrm{3}.\mathrm{31}{atm}} }{{V}\mid_{\mathrm{3}.\mathrm{31}{atm}} =\mathrm{10}\:{l}} \\ $$$$\Rightarrow\:\left(\bigtriangleup{V}\right)_{\mathrm{1}{atm}} =\left(\bigtriangleup{V}\right)_{\mathrm{3}.\mathrm{31}{atm}} ×\mathrm{3}.\mathrm{31} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{10}×\frac{\mathrm{0}.\mathrm{31}}{\mathrm{3}.\mathrm{31}}×\mathrm{3}.\mathrm{31} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\mathrm{3}.\mathrm{1}\:{litres}. \\ $$

Commented by Tinkutara last updated on 16/May/18

Answer of (b) part is not correct Sir.

Commented by ajfour last updated on 17/May/18

what's the correct answer?

Commented by Tinkutara last updated on 17/May/18

Your answer is correct Sir. Thanks a lot!

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