Question Number 31957 by Tinkutara last updated on 17/Mar/18 | ||
Commented by Tinkutara last updated on 17/Mar/18 | ||
In this question two answers are possible. Are both correct? | ||
Answered by ajfour last updated on 19/Mar/18 | ||
$${If}\:\mathrm{10}{N}\:{force}\:{is}\:{load}, \\ $$$$\frac{{load}}{{effort}}=\:{mech}.\:{adv}. \\ $$$${effort}=\frac{{load}}{{mech}.\:{adv}.}=\frac{\mathrm{10}{N}}{\mathrm{100}}\:=\:\mathrm{0}.\mathrm{1}{N} \\ $$$${effort}\:{arm}×{effort}=\:{load}\:{arm}×{load} \\ $$$$\Rightarrow\:{effort}\:{arm}\:=\frac{\mathrm{20}{cm}×\mathrm{10}{N}}{\mathrm{0}.\mathrm{1}{N}}=\mathrm{20}{m} \\ $$$${if}\:\mathrm{10}{N}\:=\:{effort} \\ $$$$\frac{{load}}{{effort}}=\:{mech}.\:{adv}. \\ $$$$\Rightarrow\:{load}\:=\:\mathrm{10}{N}×\mathrm{100}\:=\:\mathrm{1000}{N} \\ $$$${effort}\:{arm}×{effort}=\:{load}\:{arm}×{load} \\ $$$$\Rightarrow\:{load}\:{arm}\:=\:\frac{\mathrm{20}{cm}×\mathrm{10}{N}}{\mathrm{1000}{N}}=\:\mathrm{2}{mm}\:. \\ $$ | ||
Commented by Tinkutara last updated on 19/Mar/18 | ||
Thank you Sir! Is it always specified in these types of questions effort and load arm? | ||