Question Number 30106 by naka3546 last updated on 16/Feb/18 | ||
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Answered by mrW2 last updated on 16/Feb/18 | ||
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Commented by mrW2 last updated on 16/Feb/18 | ||
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$$\frac{{DG}}{{AD}}=\frac{{EF}}{{AF}} \\ $$$$\Rightarrow\frac{{DG}}{\mathrm{8}}=\frac{\mathrm{6}}{{AF}} \\ $$$$\Rightarrow{AF}×{DG}=\mathrm{6}×\mathrm{8}=\mathrm{48} \\ $$$$\left[{ABF}\right]=\left[{AFD}\right]=\frac{\mathrm{1}}{\mathrm{2}}{AF}×{DG}=\frac{\mathrm{48}}{\mathrm{2}}=\mathrm{24} \\ $$ | ||
Commented by ajfour last updated on 16/Feb/18 | ||
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$${Great}\:{question},\:{awesome}\:{solution},\:{Sir}\:! \\ $$ | ||