Question Number 28921 by 803jaideep@gmail.com last updated on 01/Feb/18 | ||
![]() | ||
Answered by Joel578 last updated on 01/Feb/18 | ||
![]() | ||
$$\mathrm{10cos}\:\left(\mathrm{200}{t}\right)\:=\:\mathrm{8} \\ $$$$\mathrm{cos}\:\left(\mathrm{200}{t}\right)\:=\:\mathrm{0}.\mathrm{8} \\ $$$$\mathrm{200}{t}\:=\:\mathrm{cos}^{−\mathrm{1}} \left(\mathrm{0}.\mathrm{8}\right)\:\approx\:\mathrm{37}° \\ $$ | ||