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Question Number 220743 by Spillover last updated on 18/May/25 | ||
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Answered by som(math1967) last updated on 18/May/25 | ||
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$$\:{No}\:{of}\:{way}\:\mathrm{4}\:{soldiers}\:{can}\:{be}\:{chosen} \\ $$$$=\:^{\mathrm{9}} {C}_{\mathrm{4}} =\mathrm{126} \\ $$$${when}\:{particular}\:{soldier}\:{included} \\ $$$$=\:^{\mathrm{8}} {C}_{\mathrm{3}} =\mathrm{56} \\ $$ | ||
Commented by Spillover last updated on 18/May/25 | ||
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$${correct} \\ $$ | ||