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Question Number 220743 by Spillover last updated on 18/May/25

Answered by som(math1967) last updated on 18/May/25

 No of way 4 soldiers can be chosen  =^9 C_4 =126  when particular soldier included  =^8 C_3 =56

$$\:{No}\:{of}\:{way}\:\mathrm{4}\:{soldiers}\:{can}\:{be}\:{chosen} \\ $$$$=\:^{\mathrm{9}} {C}_{\mathrm{4}} =\mathrm{126} \\ $$$${when}\:{particular}\:{soldier}\:{included} \\ $$$$=\:^{\mathrm{8}} {C}_{\mathrm{3}} =\mathrm{56} \\ $$

Commented by Spillover last updated on 18/May/25

correct

$${correct} \\ $$

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