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Question Number 219190 by fantastic last updated on 20/Apr/25

Commented by AntonCWX8 last updated on 21/Apr/25

Youtube has a lot of videos explaining this.  Search it yourself.

$${Youtube}\:{has}\:{a}\:{lot}\:{of}\:{videos}\:{explaining}\:{this}. \\ $$$${Search}\:{it}\:{yourself}. \\ $$

Answered by Marzuk last updated on 20/Apr/25

Rotating disk problem.One of the hardest  exam questions in the world.

$${Rotating}\:{disk}\:{problem}.{One}\:{of}\:{the}\:{hardest} \\ $$$${exam}\:{questions}\:{in}\:{the}\:{world}. \\ $$

Answered by mr W last updated on 21/Apr/25

(A)  ω_1 =angular speed of rotation           about z−axis  ω_1 (√(l^2 +a^2 ))=ωa  ω_1 (√(24a^2 +a^2 ))=ωa  5ω_1 =ω  ω_1 =(ω/5)  ⇒true  ......

$$\left({A}\right) \\ $$$$\omega_{\mathrm{1}} ={angular}\:{speed}\:{of}\:{rotation} \\ $$$$\:\:\:\:\:\:\:\:\:{about}\:{z}−{axis} \\ $$$$\omega_{\mathrm{1}} \sqrt{{l}^{\mathrm{2}} +{a}^{\mathrm{2}} }=\omega{a} \\ $$$$\omega_{\mathrm{1}} \sqrt{\mathrm{24}{a}^{\mathrm{2}} +{a}^{\mathrm{2}} }=\omega{a} \\ $$$$\mathrm{5}\omega_{\mathrm{1}} =\omega \\ $$$$\omega_{\mathrm{1}} =\frac{\omega}{\mathrm{5}} \\ $$$$\Rightarrow{true} \\ $$$$...... \\ $$

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