Question Number 218887 by Spillover last updated on 17/Apr/25
Answered by mr W last updated on 17/Apr/25
Commented by mr W last updated on 17/Apr/25
$$\mathrm{8}^{\mathrm{2}} +\left(\mathrm{2}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{72}=\left(\mathrm{6}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} \\ $$$$\Rightarrow\alpha=\mathrm{90}° \\ $$$${A}_{{blue}} =\frac{\mathrm{2}×\mathrm{8}\:\mathrm{sin}\:\left(\mathrm{45}°+\mathrm{90}°\right)}{\mathrm{2}}=\frac{\mathrm{8}×\sqrt{\mathrm{2}}}{\mathrm{2}}=\mathrm{4}\sqrt{\mathrm{2}} \\ $$
Commented by Spillover last updated on 17/Apr/25
$${yes}.{correct} \\ $$
Answered by Spillover last updated on 17/Apr/25
Answered by Spillover last updated on 17/Apr/25
Answered by Spillover last updated on 17/Apr/25
Answered by Spillover last updated on 17/Apr/25
