Question Number 218844 by Spillover last updated on 16/Apr/25
Answered by som(math1967) last updated on 16/Apr/25
$${let}\:{lenth}\:{of}\:{rectangle}={l},{width}={b} \\ $$$$\:\mathrm{2}{l}+\mathrm{6}{b}=\mathrm{4}{l}+\mathrm{2}{b}={side}\:{of}\:{square} \\ $$$$\Rightarrow\mathrm{4}{b}=\mathrm{2}{l}\Rightarrow{l}=\mathrm{2}{b} \\ $$$$\:{l}×{b}=\mathrm{18}\Rightarrow\mathrm{2}{b}^{\mathrm{2}} =\mathrm{18}\Rightarrow{b}=\mathrm{3},{l}=\mathrm{6} \\ $$$$\:{side}\:{of}\:{square}=\mathrm{2}×\mathrm{6}+\mathrm{6}×\mathrm{3}=\mathrm{30}{cm} \\ $$$${area}\:{of}\:{square}=\mathrm{900}{cm}^{\mathrm{2}} \\ $$$${area}\:\mathrm{24}\:{rectangles}=\mathrm{24}×\mathrm{18}=\mathrm{432}{cm}^{\mathrm{2}} \\ $$$$\:{blue}\:{area}=\mathrm{900}−\mathrm{432}=\mathrm{468}{cm}^{\mathrm{2}} \\ $$
Answered by Spillover last updated on 16/Apr/25
Answered by Spillover last updated on 16/Apr/25
Answered by Spillover last updated on 16/Apr/25
Answered by Spillover last updated on 16/Apr/25
