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Question Number 217723 by Spillover last updated on 19/Mar/25

Commented by Spillover last updated on 19/Mar/25

Answered by mr W last updated on 19/Mar/25

T=tension in string  F=T+μm_1 g   ...(i)  T=μ(m_1 g+m_2 g)+μm_1 g   ...(i)  (i)+(ii):  F=μ(3m_1 +m_2 )g

$${T}={tension}\:{in}\:{string} \\ $$$${F}={T}+\mu{m}_{\mathrm{1}} {g}\:\:\:...\left({i}\right) \\ $$$${T}=\mu\left({m}_{\mathrm{1}} {g}+{m}_{\mathrm{2}} {g}\right)+\mu{m}_{\mathrm{1}} {g}\:\:\:...\left({i}\right) \\ $$$$\left({i}\right)+\left({ii}\right): \\ $$$${F}=\mu\left(\mathrm{3}{m}_{\mathrm{1}} +{m}_{\mathrm{2}} \right){g} \\ $$

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