Previous in Probability and Statistics Next in Probability and Statistics | ||
Question Number 217617 by chidera last updated on 16/Mar/25 | ||
![]() | ||
Answered by som(math1967) last updated on 17/Mar/25 | ||
![]() | ||
$$\:{Probability}\:{a}\:{point}\:{lies}\:\bigtriangleup{ADM} \\ $$$$\:=\frac{{Ar}\bigtriangleup{ADM}}{{ABCD}}=\frac{\mathrm{1}}{\mathrm{4}} \\ $$$$\bigtriangleup{ADM}\:{but}\:{not}\:\bigtriangleup{ADN} \\ $$$$=\frac{\bigtriangleup{DOM}}{{ABCD}}=\frac{\mathrm{1}}{\mathrm{8}} \\ $$$${neither}\:\bigtriangleup{ADM}\:{nor}\:\bigtriangleup{ADN} \\ $$$$=\frac{{Ar}\:{MONBC}}{{ABCD}}=\mathrm{1}−\frac{\mathrm{3}}{\mathrm{8}}=\frac{\mathrm{5}}{\mathrm{8}} \\ $$ | ||
Commented by som(math1967) last updated on 17/Mar/25 | ||
![]() | ||