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Question Number 217593 by Spillover last updated on 16/Mar/25

Answered by mahdipoor last updated on 16/Mar/25

for example   S=32        Al=27        O=16          g/mol  Al_2 (SO_4 )_3 =2Al+3S+12O=296  g/mol

$${for}\:{example}\: \\ $$$${S}=\mathrm{32}\:\:\:\:\:\:\:\:{Al}=\mathrm{27}\:\:\:\:\:\:\:\:{O}=\mathrm{16}\:\:\:\:\:\:\:\:\:\:{g}/{mol} \\ $$$${Al}_{\mathrm{2}} \left({SO}_{\mathrm{4}} \right)_{\mathrm{3}} =\mathrm{2}{Al}+\mathrm{3}{S}+\mathrm{12}{O}=\mathrm{296}\:\:{g}/{mol} \\ $$

Commented by Spillover last updated on 16/Mar/25

thanks

$${thanks} \\ $$

Answered by Spillover last updated on 16/Mar/25

Answered by Spillover last updated on 16/Mar/25

Answered by Spillover last updated on 16/Mar/25

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