Question Number 216387 by Tawa11 last updated on 06/Feb/25 | ||
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Answered by mr W last updated on 06/Feb/25 | ||
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$$\left(\mathrm{6},\:\mathrm{0}\right)\: \\ $$$$\left(\mathrm{6}−\mathrm{6}\right)^{\mathrm{2}} +\left(\mathrm{0}−\mathrm{3}+{a}\right)^{\mathrm{2}} =\mathrm{5}^{\mathrm{2}} \\ $$$$\Rightarrow−\mathrm{3}+{a}=\mathrm{5}\:\Rightarrow{a}=\mathrm{8} \\ $$ | ||
Commented by mr W last updated on 06/Feb/25 | ||
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Commented by Tawa11 last updated on 06/Feb/25 | ||
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$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}. \\ $$ | ||