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Question Number 214447 by 2universe456 last updated on 08/Dec/24 | ||
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Commented by Frix last updated on 08/Dec/24 | ||
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$$={abc} \\ $$ | ||
Answered by Rasheed.Sindhi last updated on 09/Dec/24 | ||
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$$\begin{vmatrix}{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}\\{\mathrm{1}}&{{a}+\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}\\{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}+{b}}&{\mathrm{1}}\\{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}}&{\mathrm{1}+{c}}\end{vmatrix}\: \\ $$$${Subtract}\:\mathrm{C}_{\mathrm{1}} \:{from}\:\mathrm{C}_{\mathrm{2}} ,\mathrm{C}_{\mathrm{3}} \:\&\:\mathrm{C}_{\mathrm{4}} \\ $$$$=\begin{vmatrix}{\mathrm{1}}&{\mathrm{0}}&{\mathrm{0}}&{\mathrm{0}}\\{\mathrm{1}}&{{a}}&{\mathrm{0}}&{\mathrm{0}}\\{\mathrm{1}}&{\mathrm{0}}&{{b}}&{\mathrm{0}}\\{\mathrm{1}}&{\mathrm{0}}&{\mathrm{0}}&{{c}}\end{vmatrix}\: \\ $$$$=\begin{vmatrix}{{a}}&{\mathrm{0}}&{\mathrm{0}}\\{\mathrm{0}}&{{b}}&{\mathrm{0}}\\{\mathrm{0}}&{\mathrm{0}}&{{c}}\end{vmatrix} \\ $$$$={a}\begin{vmatrix}{{b}}&{\mathrm{0}}\\{\mathrm{0}}&{{c}}\end{vmatrix}\: \\ $$$$={a}\left({bc}−\mathrm{0}\right)={abc} \\ $$ | ||