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Question Number 214059 by RoseAli last updated on 25/Nov/24

Answered by a.lgnaoui last updated on 25/Nov/24

(x−1)(x−5) =0 { ((x_1 ={((10)/(10)) ,((−10)/(−10))})),((x_2 ={((50)/(10)) ,((−50)/(−10)) } )) :} S={((−50)/(−10)) ; ((−10)/(−10)) ; ((+10)/(+10)) ; ((+50)/(+10))}

$$\left(\mathrm{x}−\mathrm{1}\right)\left(\mathrm{x}−\mathrm{5}\right)\:=\mathrm{0}\:\:\:\: \\ $$$$\: \\ $$$$\begin{cases}{\mathrm{x}_{\mathrm{1}} \:\:\:\:=\left\{\frac{\mathrm{10}}{\mathrm{10}}\:\:,\frac{−\mathrm{10}}{−\mathrm{10}}\right\}}\\{\mathrm{x}_{\mathrm{2}} \:\:\:=\left\{\frac{\mathrm{50}}{\mathrm{10}}\:\:\:\:,\frac{−\mathrm{50}}{−\mathrm{10}}\:\:\:\right\}\:\:}\end{cases} \\ $$$$\boldsymbol{\mathrm{S}}=\left\{\frac{−\mathrm{50}}{−\mathrm{10}}\:;\:\:\frac{−\mathrm{10}}{−\mathrm{10}}\:\:;\:\frac{+\mathrm{10}}{+\mathrm{10}}\:;\:\frac{+\mathrm{50}}{+\mathrm{10}}\right\} \\ $$$$ \\ $$

Answered by A5T last updated on 25/Nov/24

(x−3)^2 ≡4(mod 10)⇒x=5,1

$$\left({x}−\mathrm{3}\right)^{\mathrm{2}} \equiv\mathrm{4}\left({mod}\:\mathrm{10}\right)\Rightarrow{x}=\mathrm{5},\mathrm{1} \\ $$

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