Question Number 213835 by BaliramKumar last updated on 18/Nov/24 | ||
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Answered by mehdee7396 last updated on 18/Nov/24 | ||
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$${OA}=\sqrt{\mathrm{13}}\:\:\&\:\:\:{OB}=\mathrm{3} \\ $$$${sin}\frac{\theta}{\mathrm{2}}=\frac{\mathrm{3}}{\:\sqrt{\mathrm{13}}}\Rightarrow{cos}\frac{\theta}{\mathrm{2}}=\frac{\mathrm{2}}{\:\sqrt{\mathrm{13}}} \\ $$$$\Rightarrow{tan}\frac{\theta}{\mathrm{2}}=\frac{\mathrm{3}}{\mathrm{2}}\Rightarrow\theta=\mathrm{2}{tan}^{−\mathrm{1}} \frac{\mathrm{3}}{\mathrm{2}}\:\:\checkmark \\ $$$$ \\ $$ | ||
Commented by mehdee7396 last updated on 18/Nov/24 | ||
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Commented by BaliramKumar last updated on 18/Nov/24 | ||
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$${thanks} \\ $$ | ||