Question Number 213534 by mr W last updated on 07/Nov/24 | ||
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Commented by York12 last updated on 07/Nov/24 | ||
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$$\mathrm{110} \\ $$ | ||
Answered by ajfour last updated on 07/Nov/24 | ||
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$${X}=\mathrm{40}°+\mathrm{70}°\:=\:\mathrm{110}° \\ $$$$\angle{ext}=\angle\left({int}.\:{opp}\right)_{\mathrm{1}} +\angle\left({int}.\:{opp}\right)_{\mathrm{2}} \\ $$$$\:\:{X}=\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{140}°+\mathrm{80}°\right)=\mathrm{110}° \\ $$ | ||
Commented by mr W last updated on 07/Nov/24 | ||
Commented by mr W last updated on 07/Nov/24 | ||
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