Question Number 213198 by Ismoiljon_008 last updated on 01/Nov/24
Answered by mr W last updated on 01/Nov/24
Commented by mr W last updated on 01/Nov/24
$${R}=\sqrt{\left(\mathrm{1}+\mathrm{1}\right)^{\mathrm{2}} +\left(\frac{\mathrm{1}}{\mathrm{2}}\right)^{\mathrm{2}} }=\frac{\sqrt{\mathrm{17}}}{\mathrm{2}} \\ $$$${x}=\sqrt{\left(\mathrm{2}{R}\right)^{\mathrm{2}} −\left(\mathrm{1}+\mathrm{1}\right)^{\mathrm{2}} }=\sqrt{\mathrm{13}}\:\:\checkmark \\ $$