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Question Number 213020 by Spillover last updated on 28/Oct/24

Commented by Ghisom last updated on 29/Oct/24

we can solve it only if the triangle is a  special one  rectangular doesn′t fit but isosceles fits  a=b=8∧c=((48)/5)  I used Heron′s Formula and its further  implications

$$\mathrm{we}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{it}\:\mathrm{only}\:\mathrm{if}\:\mathrm{the}\:\mathrm{triangle}\:\mathrm{is}\:\mathrm{a} \\ $$$$\mathrm{special}\:\mathrm{one} \\ $$$$\mathrm{rectangular}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{fit}\:\mathrm{but}\:\mathrm{isosceles}\:\mathrm{fits} \\ $$$${a}={b}=\mathrm{8}\wedge{c}=\frac{\mathrm{48}}{\mathrm{5}} \\ $$$$\mathrm{I}\:\mathrm{used}\:\mathrm{Heron}'\mathrm{s}\:\mathrm{Formula}\:\mathrm{and}\:\mathrm{its}\:\mathrm{further} \\ $$$$\mathrm{implications} \\ $$

Commented by mr W last updated on 29/Oct/24

abc=24(a+b+c)

$${abc}=\mathrm{24}\left({a}+{b}+{c}\right) \\ $$

Commented by Ghisom last updated on 29/Oct/24

yes but that′s still not enough information

$$\mathrm{yes}\:\mathrm{but}\:\mathrm{that}'\mathrm{s}\:\mathrm{still}\:\mathrm{not}\:\mathrm{enough}\:\mathrm{information} \\ $$

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