Question Number 211734 by BaliramKumar last updated on 19/Sep/24 | ||
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Answered by TonyCWX08 last updated on 19/Sep/24 | ||
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$${y}={kx}\:\Rightarrow\:{k}=\frac{{y}}{{x}} \\ $$$${z}={ky}\:\Rightarrow\:{k}=\frac{{z}}{{y}} \\ $$$$\frac{{y}}{{x}}=\frac{{z}}{{y}} \\ $$$${y}^{\mathrm{2}} ={xy}\:=\:{B} \\ $$ | ||
Commented by Ari last updated on 19/Sep/24 | ||
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$${y}^{\mathrm{2}} ={zx} \\ $$ | ||