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Question Number 211456 by BaliramKumar last updated on 09/Sep/24

Answered by A5T last updated on 09/Sep/24

max when 8cosθ−8sinθcosθ=0  ⇒cosθ=0 or sinθ=1⇒max=8×1−4×1=4

$${max}\:{when}\:\mathrm{8}{cos}\theta−\mathrm{8}{sin}\theta{cos}\theta=\mathrm{0} \\ $$$$\Rightarrow{cos}\theta=\mathrm{0}\:{or}\:{sin}\theta=\mathrm{1}\Rightarrow{max}=\mathrm{8}×\mathrm{1}−\mathrm{4}×\mathrm{1}=\mathrm{4} \\ $$

Answered by mehdee1342 last updated on 09/Sep/24

A=−4(sinθ−1)^2 +4  if   sinθ=1⇒maxA=4 ✓

$${A}=−\mathrm{4}\left({sin}\theta−\mathrm{1}\right)^{\mathrm{2}} +\mathrm{4} \\ $$$${if}\:\:\:{sin}\theta=\mathrm{1}\Rightarrow{maxA}=\mathrm{4}\:\checkmark \\ $$$$ \\ $$

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