Question Number 209883 by Ismoiljon_008 last updated on 24/Jul/24 | ||
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Commented by Ismoiljon_008 last updated on 24/Jul/24 | ||
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$$\:\:\:{help}\:,\:{please} \\ $$ | ||
Commented by Frix last updated on 25/Jul/24 | ||
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$$\mathrm{I}\:\mathrm{get}\:{x}=\mathrm{18} \\ $$$${AB}={BD}={CD}=\mathrm{6}\sqrt{\mathrm{5}} \\ $$$${BE}=\mathrm{12}\sqrt{\mathrm{2}} \\ $$$${CE}=\mathrm{12} \\ $$ | ||
Answered by mr W last updated on 25/Jul/24 | ||
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Commented by mr W last updated on 25/Jul/24 | ||
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$${a}=\mathrm{6}\sqrt{\mathrm{5}} \\ $$$${x}+\mathrm{12}=\sqrt{\mathrm{5}}{a}=\mathrm{30} \\ $$$$\Rightarrow{x}=\mathrm{18} \\ $$ | ||
Commented by Ismoiljon_008 last updated on 25/Jul/24 | ||
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$$\:\:\:{Sorry},\:{please}\:{interpret}\:{me}\:{that}\:{how} \\ $$$$\:\:\:\angle{BAD}\:=\:\mathrm{45}^{{o}} \: \\ $$ | ||
Commented by mr W last updated on 25/Jul/24 | ||
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$${ABDE}\:{are}\:{cyclic},\:{see}\:{below}. \\ $$ | ||
Commented by mr W last updated on 25/Jul/24 | ||
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Commented by Ismoiljon_008 last updated on 25/Jul/24 | ||
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$$\:\:{ok},\:{I}\:{get}\:{it}.\:{Thank}\:{you}\:{very}\:{much} \\ $$ | ||