Question Number 209288 by Jubr last updated on 06/Jul/24
Answered by A5T last updated on 06/Jul/24
![(x/r)=(8/r)⇒x=8 r^2 =(2x)^2 +(r−8)^2 ⇒r=20 [Yellow]=((90)/(360))×400π−((20×20)/2)=100π−200](Q209291.png)
$$\frac{{x}}{{r}}=\frac{\mathrm{8}}{{r}}\Rightarrow{x}=\mathrm{8} \\ $$$${r}^{\mathrm{2}} =\left(\mathrm{2}{x}\right)^{\mathrm{2}} +\left({r}−\mathrm{8}\right)^{\mathrm{2}} \Rightarrow{r}=\mathrm{20} \\ $$$$\left[{Yellow}\right]=\frac{\mathrm{90}}{\mathrm{360}}×\mathrm{400}\pi−\frac{\mathrm{20}×\mathrm{20}}{\mathrm{2}}=\mathrm{100}\pi−\mathrm{200} \\ $$
Commented by Tawa11 last updated on 06/Jul/24
$$\mathrm{weldone}\:\mathrm{sir} \\ $$
Commented by Jubr last updated on 06/Jul/24
$${Thanks}\:{sir} \\ $$